3ΩΡΟ ΔΙΑΓΩΝΙΣΜΑ ΜΙΓΑΔΙΚΩΝ 15 10 2011 Α1

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- M. 11.10 ***4 **** 3/ *** 15/10/2011 1 |z w||z||w| = z, w C e _7 2 _4 3 z _4 4 _10 i 0 + = , 0 = 0 = y y ' vvz z = *v N e z C e z, w , . z w z w z w s + s + z, w C e : iz i=+, R e .1 :z i = _4 B2 v (1 z) (1 z) + = _7 3 2 3 98 991 z z z ... z z 0 + + + + + + = _7 4 w w 1 3z 2 + sw 3 z 2 + s _7 3 25 = zw i z 3i 4 5 = w i4= + . 1) zw_6 2) z _6 3) z w _7 4) 1 z 3 9 s s _6 zw z R e4w zz= + .1) w x x ' , z _5 A 1 2 3z , z , z , 2) 11z 14 z= 22z 14 z= _2 3) ( )1 21 21 1z z 4z z| |+ + s |\ . _5 4) 1 2 2 3 3 11 2 3z z z z z z2z z z+ +=+ +_6 5) 2 3 3 1 1 23 1 2z z z z z zz z z + + _7