5. απαντησεις αρμονικο κυμα 2017 red

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    21-Jan-2018

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<ol><li> 1. 1 4 2017 1 4 . A1. , xx, t. =9 rad, : . . . . . 5 , . </li><li> 2. 2 : . xOx : , . , , , ! yZ = A =13 yZ = A 13( ) yZ = 0 uZ = = 13( )uZ = 0,8s, : , , . x . t=0 (x=0) y=0,2t (S.I.), , , . x , t=0,4s. : 1. , f u . 2. , m=10-4 kg, u=umax/2, umax . u = f = u f = 0,4m uZ =2 ft xZ xZ =0 ,8m uZ = 2 2,5t 2( )( S.I.) t 0,8s uZ = 2 2,5t2 2( )= 2 2,25 2( )= 2 uZ = 0 </li><li> 9. 9 3. (x=1,2m) . , t . 4. t1=0,4s t2=0,75s. 2 = 10. 6+6+7+6=25 1. , : : t=0,4s : , f: : u : y = A2 ft x = 2 ft x = 2 f 0,4 x (1) x = 0 ( 1) = 4 rad 4 = 2 f 0,4( ) 2 = f 0,4 f = 5Hz = 1 f T = 1 5 s T = 0,2s = 0 ( 1) x = 0,8m0 = 2 5 0,4 0,8 5 0,4 0,8 = 0 5 0,4 = 0,8 5 = 2 = 2 5 = 0,4m u = f u = 0,45 u = 2m / s </li><li> 10. 10 : 2. D : () : : , : 3. , x=1,2m , : t=0,6s, ! y = 0,22 5t 2,5x( ) ( S.I.) D = m 2 = 2 f = 10 r / s D = m 2 D = 104 100 2 D = 0,1 / m = 1 2 DA2 E = 1 2 0,10,04 E = 2103 J K = 1 2 mu2 = 1 2 m umax 2 2 = 1 2 m umax 2 4 = 1 4 1 2 mumax 2 K = E 4 E = K +U U = E K U = E E 4 U = 3E 4 U = 1,5 103 J y = 0,22 5t 3( )( S.I.) t 0,6s </li><li> 11. 11 yK=f(t), t y=-A , : , y=-A, : 4. : t=0,4s &lt; 0,6s, , . t=0,75s: t = 0,6 + 3T 4 = 0,6 +0,75 0,2 = 0,6 +0,15 t = 0,75s y = 0,22 5t 3( ) y =0 ,2m 0,2 = 0,22 5t 3( )2 5t 3( )= 1 2 5t 3( )= 3 2 2 5t 3( )= 2 + 3 2 1 =0 2 5t 3( )= 3 2 2 5t 3( )= 3 2 5t 3 = 3 4 5t = 3+0,75 5t = 3,75 t = 0,75s = 2 2 5t 3( ) = 100 2 0,22 5t 3( ) = 2002 5t 3( )( S.I.) = 2002 5t 3( ) t=0 ,75 s = 2002 5 0,75 3( ) </li><li> 12. 12 , : , t=0,75s yK=-A, : Ox , =2m/s. O(x=0) t=0 . , d=0,8m, 40 2s. 1. . 2. x1=+0,4m x2=+0,75m , =f(t). 3. y=+A , y . 4. t1=0,375 s x , y</li></ol>